1.

In ≈í√Æ PQR, PS is the bisector of ‚Äö√ ‚Ä ¬¨‚Ä P and PT ‚Äö√§‚Ä¢ OR, then ‚Äö√ ‚Ä ¬¨‚Ä TPS is equal to:$

A. ‚Äö√ ‚Ä Q + ‚Äö√ ‚Ä R
B. 900 + 1/2 ‚Äö√ ‚Ä Q
C. 900 - 1/2 ‚Äö√ ‚Ä R
D. 1/2 (‚Äö√ ‚Ä Q - ‚Äö√ ‚Ä R)
Answer» E.


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