1.

__In Δ ABC, AD ⊥ BC, then__

A. AB2 - BD2 = AC2 - CD2
B. AB2 + BD2 = AC2 - CD2
C. AB2 - BD2 = AC2 + CD2
D. AB2 - AC2 = BD2 + CD2
Answer» B. AB2 + BD2 = AC2 - CD2


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