In \[\Delta ABC\] the mid-point of the sides AB, BC and CA are respectively (l, 0, 0), (0, m, 0) and (0, 0, n). Then, \[\frac{A{{B}^{2}}+B{{C}^{2}}+C{{A}^{2}}}{{{l}^{2}}+{{m}^{2}}+{{n}^{2}}}\] is equal to

In \[\Delta ABC\] the mid-point of the sides AB, BC and CA are respect

1.	In \[\Delta ABC\] the mid-point of the sides AB, BC and CA are respectively (l, 0, 0), (0, m, 0) and (0, 0, n). Then, \[\frac{A{{B}^{2}}+B{{C}^{2}}+C{{A}^{2}}}{{{l}^{2}}+{{m}^{2}}+{{n}^{2}}}\] is equal to
A.	2
B.	4
C.	8
D.	16
Answer» D. 16

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In \[\Delta ABC\] the mid-point of the sides AB, BC and CA are respectively (l, 0, 0), (0, m, 0) and (0, 0, n). Then, \[\frac{A{{B}^{2}}+B{{C}^{2}}+C{{A}^{2}}}{{{l}^{2}}+{{m}^{2}}+{{n}^{2}}}\] is equal to

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