In \[\Delta ABC\], if \[2s=a+b+c\], then the value of \[\frac{s(s-a)}{bc}-\frac{(s-b)(s-c)}{bc}=\]

In \[\Delta ABC\], if \[2s=a+b+c\], then the value of \[\frac{s(s-a)}{

1.	In \[\Delta ABC\], if \[2s=a+b+c\], then the value of \[\frac{s(s-a)}{bc}-\frac{(s-b)(s-c)}{bc}=\]
A.	\[\sin A\]
B.	\[\cos A\]
C.	\[\tan A\]
D.	None of these
Answer» C. \[\tan A\]

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In \[\Delta ABC\], if \[2s=a+b+c\], then the value of \[\frac{s(s-a)}{bc}-\frac{(s-b)(s-c)}{bc}=\]

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