In \[\Delta \,ABC\], \[\frac{\cos \frac{1}{2}(B-C)}{\sin \frac{1}{2}A}=\] [MP PET 1993; Roorkee 1973]

In \[\Delta \,ABC\], \[\frac{\cos \frac{1}{2}(B-C)}{\sin \frac{1}{2}A}

1.	In \[\Delta \,ABC\], \[\frac{\cos \frac{1}{2}(B-C)}{\sin \frac{1}{2}A}=\] [MP PET 1993; Roorkee 1973]
A.	\[\frac{b-c}{a}\]
B.	\[\frac{b+c}{a}\]
C.	\[\frac{a}{b-c}\]
D.	\[\frac{a}{b+c}\]
Answer» C. \[\frac{a}{b-c}\]

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In \[\Delta \,ABC\], \[\frac{\cos \frac{1}{2}(B-C)}{\sin \frac{1}{2}A}=\] [MP PET 1993; Roorkee 1973]

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