In \[\Delta ABC\], \[c\cos (A-\alpha )+a\cos (C+\alpha )=\]

1.	In \[\Delta ABC\], \[c\cos (A-\alpha )+a\cos (C+\alpha )=\]
A.	\[a\cos \alpha \]
B.	\[b\cos \alpha \]
C.	\[c\cos \alpha \]
D.	\[2b\cos \alpha \]
Answer» C. \[c\cos \alpha \]

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In \[\Delta ABC\], \[c\cos (A-\alpha )+a\cos (C+\alpha )=\]

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