1.

In an experiment, the following observation's were recorded : L = 2.820 m, M = 3.00 kg, l = 0.087 cm, Diameter D = 0.041 cm Taking g = 9.81 \[m/{{s}^{2}}\]using the formula , Y=\[\frac{4MgL}{\pi {{D}^{2}}l}\], the maximum permissible error in Y is 

A.            7.96%                                      
B.            4.56%
C.            6.50%                                      
D.            8.42%
Answer» D.            8.42%


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