

MCQOPTIONS
Saved Bookmarks
1. |
In a wetted-wall tower, an air-H2S mixture is flowing by a film of water which is flowing as a thin film down a vertical plate. The H2S is being absorbed from the air to the water at a total pressure of 1.50 atm abs and 30oC. The value of kc of 9.567×10-4 m/s has been predicted for the gas-phase mass-transfer coefficient. At a given point the mole fraction of H2S in the liquid at the liquid-gas interface is 2.0×10-5 and pA of H2S in the gas is 0.05 atm. The Henry’s law equilibrium relation is pA(atm) = 609xA (mole fraction in liquid). Calculate the rate of absorption of H2S.$ |
A. | 1.480√ó10-3 kmol/m<sup>2</sup>.s |
B. | 1.486√ó10-3 kmol/m<sup>2</sup>.s |
C. | 1.485√ó10-3 kmol/m<sup>2</sup>.s |
D. | 1.487√ó10-3 kmol/m<sup>2</sup>.s |
Answer» C. 1.485‚Äö√†√∂‚àö‚â•10-3 kmol/m<sup>2</sup>.s | |