1.

In a wetted-wall tower, an air-H2S mixture is flowing by a film of water which is flowing as a thin film down a vertical plate. The H2S is being absorbed from the air to the water at a total pressure of 1.50 atm abs and 30oC. The value of kc of 9.567×10-4 m/s has been predicted for the gas-phase mass-transfer coefficient. At a given point the mole fraction of H2S in the liquid at the liquid-gas interface is 2.0×10-5 and pA of H2S in the gas is 0.05 atm. The Henry’s law equilibrium relation is pA(atm) = 609xA (mole fraction in liquid). Calculate the rate of absorption of H2S.$

A. 1.480√ó10-3 kmol/m<sup>2</sup>.s
B. 1.486√ó10-3 kmol/m<sup>2</sup>.s
C. 1.485√ó10-3 kmol/m<sup>2</sup>.s
D. 1.487√ó10-3 kmol/m<sup>2</sup>.s
Answer» C. 1.485‚Äö√†√∂‚àö‚â•10-3 kmol/m<sup>2</sup>.s


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