In a uniform magnetic field of induction B a wire in the form of a semicircle of radius r rotates about the diameter of the circle with an angular frequency $$\omega $$. The axis of rotation is perpendicular to the field. If the total resistance of the circuit is R, the mean power generated per period of rotation is

Question

TuteeHUB · Accepted Answer

$$\frac{B\pi {{r}^{2}}\omega }{2R}$$

TuteeHUB · Answer

$$\frac{{{(B\pi r\omega )}^{2}}}{2R}$$

TuteeHUB · Answer

$$\frac{{{(B\pi {{r}^{2}}\omega )}^{2}}}{8R}$$

TuteeHUB · Answer

$$\frac{{{(B\pi r{{\omega }^{2}})}^{2}}}{8R}$$

1.	In a uniform magnetic field of induction B a wire in the form of a semicircle of radius r rotates about the diameter of the circle with an angular frequency \[\omega \]. The axis of rotation is perpendicular to the field. If the total resistance of the circuit is R, the mean power generated per period of rotation is
A.	\[\frac{{{(B\pi r\omega )}^{2}}}{2R}\]
B.	\[\frac{{{(B\pi {{r}^{2}}\omega )}^{2}}}{8R}\]
C.	\[\frac{B\pi {{r}^{2}}\omega }{2R}\]
D.	\[\frac{{{(B\pi r{{\omega }^{2}})}^{2}}}{8R}\]
Answer» C. \[\frac{B\pi {{r}^{2}}\omega }{2R}\]

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