In a triangle with one angle of \[{{120}^{o}}\]the lengths of the sides form an A. P. If the length of the greatest side is \[7cm\], the area of triangle is

\[\frac{3\sqrt{15}}{4}c{{m}^{2}}\]

\[\frac{15\sqrt{3}}{4}c{{m}^{2}}\]

\[\frac{3\sqrt{3}}{4}c{{m}^{2}}\]

In a triangle with one angle of \[{{120}^{o}}\]the lengths of the side

1.	In a triangle with one angle of \[{{120}^{o}}\]the lengths of the sides form an A. P. If the length of the greatest side is \[7cm\], the area of triangle is
A.	\[\frac{3\sqrt{15}}{4}c{{m}^{2}}\]
B.	\[\frac{15\sqrt{3}}{4}c{{m}^{2}}\]
C.	\[\frac{15}{4}c{{m}^{2}}\]
D.	\[\frac{3\sqrt{3}}{4}c{{m}^{2}}\]
Answer» C. \[\frac{15}{4}c{{m}^{2}}\]

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In a triangle with one angle of \[{{120}^{o}}\]the lengths of the sides form an A. P. If the length of the greatest side is \[7cm\], the area of triangle is

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