In a triangle \[ABC\] the value of \[\angle A\] is given by \[5\cos A+ – McqOptions

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1.	In a triangle \[ABC\] the value of \[\angle A\] is given by \[5\cos A+3=0\], then the equation whose roots are \[\sin A\] and \[\tan A\] will be [Roorkee 1972]
A.	\[15{{x}^{2}}-8x+16=0\]
B.	\[15{{x}^{2}}+8x-16=0\]
C.	\[15{{x}^{2}}-8\sqrt{2}x+16=0\]
D.	\[15{{x}^{2}}-8x-16=0\]
Answer» C. \[15{{x}^{2}}-8\sqrt{2}x+16=0\]

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