In a triangle \[ABC\], \[AD\] is altitude from A. Given \[b>c,\] \[\angle C={{23}^{o}}\]and \[AD=\frac{abc}{{{b}^{2}}-{{c}^{2}}},\]then \[\angle B=\] [IIT 1994]

In a triangle \[ABC\], \[AD\] is altitude from A. Given \[b>c,\] \[\an

1.	In a triangle \[ABC\], \[AD\] is altitude from A. Given \[b>c,\] \[\angle C={{23}^{o}}\]and \[AD=\frac{abc}{{{b}^{2}}-{{c}^{2}}},\]then \[\angle B=\] [IIT 1994]
A.	\[{{67}^{o}}\]
B.	\[{{44}^{o}}\]
C.	\[{{113}^{o}}\]
D.	None of these
Answer» D. None of these

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In a triangle \[ABC\], \[AD\] is altitude from A. Given \[b>c,\] \[\angle C={{23}^{o}}\]and \[AD=\frac{abc}{{{b}^{2}}-{{c}^{2}}},\]then \[\angle B=\] [IIT 1994]

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