In a trapezium, the vector \[\overrightarrow{BC}=\lambda \overrightarrow{AD}.\] We will then find that \[\mathbf{p}=\overrightarrow{AC}+\overrightarrow{BD}\] is collinear with \[\overrightarrow{AD},\] If \[\mathbf{p}=\mu \overrightarrow{AD},\] then

In a trapezium, the vector \[\overrightarrow{BC}=\lambda \overrightarr

1.	In a trapezium, the vector \[\overrightarrow{BC}=\lambda \overrightarrow{AD}.\] We will then find that \[\mathbf{p}=\overrightarrow{AC}+\overrightarrow{BD}\] is collinear with \[\overrightarrow{AD},\] If \[\mathbf{p}=\mu \overrightarrow{AD},\] then
A.	\[\mu =\lambda +1\]
B.	\[\lambda =\mu +1\]
C.	\[\lambda +\mu =1\]
D.	\[\mu =2+\lambda \]
Answer» B. \[\lambda =\mu +1\]

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In a trapezium, the vector \[\overrightarrow{BC}=\lambda \overrightarrow{AD}.\] We will then find that \[\mathbf{p}=\overrightarrow{AC}+\overrightarrow{BD}\] is collinear with \[\overrightarrow{AD},\] If \[\mathbf{p}=\mu \overrightarrow{AD},\] then

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