In a transistor CE mode, VCC = +30 V. If the transistor is in cut off – McqOptions

MCQOPTIONS

1.	In a transistor CE mode, VCC = +30 V. If the transistor is in cut off region, VCE =
A.	+30 V
B.	+20 V
C.	10 V
D.	zero
Answer» B. +20 V

Discussion

No Comment Found

Related MCQs

A CB amplifier has re = 6 , RL = 600 and a = 0.98. The voltage gain is
Consider the following statements : A clamper circuit 1.adds or subtracts a dc voltage to a waveform 2.does not change the waveform 3.amplifiers the waveform Which are correct?
A forward voltage of 9 V is applied to a diode in series with a 1 k load resistor. The voltage across load resistor is zero. It indicates that
Assertion (A): CE amplifier is the most widely used BJT amplifier Reason (R): CE amplifier has zero phase difference between input and output
Assertion (A): For large signal variations an amplifier circuit has to be analysed graphically Reason (R): The output characteristics of a transistor is nonlinear.
In a BJT circuit a pnp transistor is replaced by npn transistor. To analyse the new circuit
The load impedance ZL of a CE amplifier has R and L in series. The phase difference between output and input will be
For a base current of 10 A, what is the value of collector current in common emitter if dc = 100
The quiescent collector current IC, and collector to emitter voltage VCE in a CE connection are the values when
A half wave diode rectifier has a capacitance input filter. If input voltage is Vm sin t, PIV is