In a Thomson set-up for the determination of e/m, electrons accelerated by 2.5 $$kV$$ enter the region of crossed electric and magnetic fields of strengths $$3.6\times {{10}^{4}}V{{m}^{-1}}$$ and $$1.2\times {{10}^{-3}}T$$ respectively and go through undeflected. The measured value of $$e/m$$ of the electron is equal to [AMU 2002]

Question

In a Thomson set-up for the determination of e/m, electrons accelerated by 2.5 $$kV$$ enter the region of crossed electric and magnetic fields of strengths $$3.6\times {{10}^{4}}V{{m}^{-1}}$$ and $$1.2\times {{10}^{-3}}T$$ respectively and go through undeflected. The measured value of $$e/m$$ of the electron is equal to       [AMU 2002]

TuteeHUB · Accepted Answer

$$1.85\times {{10}^{11}}C\text{-}k{{g}^{-1}}$$

TuteeHUB · Answer

$$1.0\times {{10}^{11}}C\text{-}k{{g}^{-1}}$$

TuteeHUB · Answer

$$1.76\times {{10}^{11}}C\text{-}k{{g}^{-1}}$$

TuteeHUB · Answer

$$1.80\times {{10}^{11}}C\text{-}k{{g}^{-1}}$$

1.	In a Thomson set-up for the determination of e/m, electrons accelerated by 2.5 \[kV\] enter the region of crossed electric and magnetic fields of strengths \[3.6\times {{10}^{4}}V{{m}^{-1}}\] and \[1.2\times {{10}^{-3}}T\] respectively and go through undeflected. The measured value of \[e/m\] of the electron is equal to [AMU 2002]
A.	\[1.0\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
B.	\[1.76\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
C.	\[1.80\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
D.	\[1.85\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
Answer» D. \[1.85\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]

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