MCQOPTIONS
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| 1. |
In a photo-emissive cell, with exciting wavelength\[\lambda \], the maximum kinetic energy of electron is K. If the exciting wavelength is changed to \[3\lambda /4\] the kinetic energy of the fastest emitted electron will be |
| A. | 3K/4 |
| B. | 4K/3 |
| C. | less than 4K/3 |
| D. | greater than 4K/3 |
| Answer» E. | |