1.

In a photo-emissive cell, with exciting wavelength\[\lambda \], the maximum kinetic energy of electron is K.  If the exciting wavelength is changed to \[3\lambda /4\] the kinetic energy of the fastest emitted electron will be

A. 3K/4                             
B. 4K/3
C. less than 4K/3  
D.        greater than 4K/3
Answer» E.


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