In a mixture, unbroken and broken rice grains are in the ratio 3 : 2. – McqOptions

MCQOPTIONS

1.	In a mixture, unbroken and broken rice grains are in the ratio 3 : 2. How much fraction of the mixture must be drawn off and substituted with broken grains, so that the ratio of unbroken and broken grains becomes 1 : 1?
A.	1/3
B.	1/6
C.	1/4
D.	2/5
Answer» C. 1/4

Discussion

No Comment Found

Related MCQs

In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:
If Rs. 782 be divided into three parts, proportional to : : , then the first part is:
A sum of Rs. 2880 is divided into two parts in a ratio of 7 : 11. The larger part will be:
Divide 170 into three parts such that the first part is 10 more than the second and its ratio with the third part is 2 : 5
If two- third of A is four-fifth B, then A: B =?
A bag contains coins of 1 rupees, 50 paise and 25 paise in the ratio of 1 : 2 : 4. If the total money in the bag is Rs. 225, then how many 50 paise coins are there?
Find the fourth proportional to 3.6, 6.9, and 11.4.A. 20.3B. 18.9C. 19.6D. 21.85
A certain sum is divided between A, B. C and D such that the ratio of shares of A and B is 4 : 3, that of B and C is 5 : 8 and that of C and D is 2 : 5. If the difference between the shares of B and D is Rs. 2,250, then the original sum is:
A sum of Rs. 4,360 was to be divided among A, B, C and D in the ratio 3 ∶ 4 ∶ 5 ∶ 8, but it was divided in the ratio \(\dfrac{1}{3} : \dfrac{1}{4} : \dfrac{1}{5} : \dfrac{1}{8}\) by mistake. Which of the following statements will hold true as a result?
If 30% of A = 0.25 of B = 1/5h part of C, then A : B : C =