In a \[\Delta ABC,\]\[\frac{\sin A}{\sin C}=\frac{\sin (A-B)}{\sin (B-C)},\] then \[{{a}^{2}},{{b}^{2}},{{c}^{2}}\] are such that

\[{{b}^{2}}={{a}^{2}}+{{c}^{2}}\]

\[{{b}^{2}}=\frac{{{a}^{2}}{{c}^{2}}}{{{a}^{2}}+{{c}^{2}}}\]

In a \[\Delta ABC,\]\[\frac{\sin A}{\sin C}=\frac{\sin (A-B)}{\sin (B-

1.	In a \[\Delta ABC,\]\[\frac{\sin A}{\sin C}=\frac{\sin (A-B)}{\sin (B-C)},\] then \[{{a}^{2}},{{b}^{2}},{{c}^{2}}\] are such that
A.	\[{{b}^{2}}=ac\]
B.	\[{{b}^{2}}=\frac{{{a}^{2}}{{c}^{2}}}{{{a}^{2}}+{{c}^{2}}}\]
C.	They are in A.P.
D.	\[{{b}^{2}}={{a}^{2}}+{{c}^{2}}\]
Answer» D. \[{{b}^{2}}={{a}^{2}}+{{c}^{2}}\]

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In a \[\Delta ABC,\]\[\frac{\sin A}{\sin C}=\frac{\sin (A-B)}{\sin (B-C)},\] then \[{{a}^{2}},{{b}^{2}},{{c}^{2}}\] are such that

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