In a \[\Delta ABC\], \[b=2,C={{60}^{o}},c=\sqrt{6}\], then a =

1.	In a \[\Delta ABC\], \[b=2,C={{60}^{o}},c=\sqrt{6}\], then a =
A.	\[\sqrt{3}-1\]
B.	\[\sqrt{3}\]
C.	\[\sqrt{3}+1\]
D.	None of these
Answer» D. None of these

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In a \[\Delta ABC\], \[b=2,C={{60}^{o}},c=\sqrt{6}\], then a =

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