If\[\frac{2\sin \alpha }{\{1+\cos \alpha +\sin \alpha \}}=y,\]then \[\frac{\{1-\cos \alpha +\sin \alpha \}}{1+\sin \alpha }=\] [BIT Ranchi 1996; Orissa JEE 2004]

If\[\frac{2\sin \alpha }{\{1+\cos \alpha +\sin \alpha \}}=y,\]then \[\

1.	If\[\frac{2\sin \alpha }{\{1+\cos \alpha +\sin \alpha \}}=y,\]then \[\frac{\{1-\cos \alpha +\sin \alpha \}}{1+\sin \alpha }=\] [BIT Ranchi 1996; Orissa JEE 2004]
A.	\[\frac{1}{y}\]
B.	\[y\]
C.	\[1-y\]
D.	\[1+y\]
Answer» C. \[1-y\]

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If\[\frac{2\sin \alpha }{\{1+\cos \alpha +\sin \alpha \}}=y,\]then \[\frac{\{1-\cos \alpha +\sin \alpha \}}{1+\sin \alpha }=\] [BIT Ranchi 1996; Orissa JEE 2004]

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