If \[z=\frac{{{({{x}^{4}}+{{y}^{4}})}^{1/3}}}{{{({{x}^{3}}+{{y}^{3}})}^{1/4}}}\], then \[x\frac{\partial z}{\partial x}+y\frac{\partial z}{\partial y}=\]

If \[z=\frac{{{({{x}^{4}}+{{y}^{4}})}^{1/3}}}{{{({{x}^{3}}+{{y}^{3}})}

1.	If \[z=\frac{{{({{x}^{4}}+{{y}^{4}})}^{1/3}}}{{{({{x}^{3}}+{{y}^{3}})}^{1/4}}}\], then \[x\frac{\partial z}{\partial x}+y\frac{\partial z}{\partial y}=\]
A.	\[\frac{1}{12}z\]
B.	\[\frac{1}{4}z\]
C.	\[\frac{1}{3}z\]
D.	\[\frac{7}{12}z\]
Answer» E.

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If \[z=\frac{{{({{x}^{4}}+{{y}^{4}})}^{1/3}}}{{{({{x}^{3}}+{{y}^{3}})}^{1/4}}}\], then \[x\frac{\partial z}{\partial x}+y\frac{\partial z}{\partial y}=\]

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