If \[z=\frac{\pi }{4}{{(1+i)}^{4}}\left( \frac{1-\sqrt{\pi }i}{\sqrt{\pi }+i}+\frac{\sqrt{\pi }-i}{1+\sqrt{\pi }i} \right),\] then \[\left( \frac{|z|}{am{{p}^{(z)}}} \right)\] equals

If \[z=\frac{\pi }{4}{{(1+i)}^{4}}\left( \frac{1-\sqrt{\pi }i}{\sqrt{\

1.	If \[z=\frac{\pi }{4}{{(1+i)}^{4}}\left( \frac{1-\sqrt{\pi }i}{\sqrt{\pi }+i}+\frac{\sqrt{\pi }-i}{1+\sqrt{\pi }i} \right),\] then \[\left( \frac{\|z\|}{am{{p}^{(z)}}} \right)\] equals
A.	1
B.	\[\pi \]
C.	\[3\pi \]
D.	4
Answer» E.

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If \[z=\frac{\pi }{4}{{(1+i)}^{4}}\left( \frac{1-\sqrt{\pi }i}{\sqrt{\pi }+i}+\frac{\sqrt{\pi }-i}{1+\sqrt{\pi }i} \right),\] then \[\left( \frac{|z|}{am{{p}^{(z)}}} \right)\] equals

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