If \[z=\frac{-2\left( 1+2i \right)}{3+i}\] where \[i=\sqrt{-1},\] then argument \[\theta \,(-\pi

If \[z=\frac{-2\left( 1+2i \right)}{3+i}\] where \[i=\sqrt{-1},\] then

1.	If \[z=\frac{-2\left( 1+2i \right)}{3+i}\] where \[i=\sqrt{-1},\] then argument \[\theta \,(-\pi
A.	\[\frac{3\pi }{4}\]
B.	\[\frac{\pi }{4}\]
C.	\[\frac{5\pi }{6}\]
D.	\[-\frac{3\pi }{4}\]
Answer» C. \[\frac{5\pi }{6}\]

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If \[z=\frac{-2\left( 1+2i \right)}{3+i}\] where \[i=\sqrt{-1},\] then argument \[\theta \,(-\pi

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