If \[{{z}^{2}}=\frac{{{x}^{1/2}}+{{y}^{1/2}}}{{{x}^{1/3}}+{{y}^{1/3}}}\] then \[x\frac{\partial z}{\partial x}+y\frac{\partial z}{\partial y}=\] [EAMCET 1999]

If \[{{z}^{2}}=\frac{{{x}^{1/2}}+{{y}^{1/2}}}{{{x}^{1/3}}+{{y}^{1/3}}}

1.	If \[{{z}^{2}}=\frac{{{x}^{1/2}}+{{y}^{1/2}}}{{{x}^{1/3}}+{{y}^{1/3}}}\] then \[x\frac{\partial z}{\partial x}+y\frac{\partial z}{\partial y}=\] [EAMCET 1999]
A.	\[\frac{z}{6}\]
B.	\[\frac{z}{3}\]
C.	\[\frac{z}{2}\]
D.	\[\frac{z}{12}\]
Answer» E.

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If \[{{z}^{2}}=\frac{{{x}^{1/2}}+{{y}^{1/2}}}{{{x}^{1/3}}+{{y}^{1/3}}}\] then \[x\frac{\partial z}{\partial x}+y\frac{\partial z}{\partial y}=\] [EAMCET 1999]

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