If \[|z|\,=1,(z\ne -1)\]and \[z=x+iy,\]then \[\left( \frac{z-1}{z+1} \right)\] is [RPET 1997]

If \[|z|\,=1,(z\ne -1)\]and \[z=x+iy,\]then \[\left( \frac{z-1}{z+1}

1.	If \[\|z\|\,=1,(z\ne -1)\]and \[z=x+iy,\]then \[\left( \frac{z-1}{z+1} \right)\] is [RPET 1997]
A.	Purely real
B.	Purely imaginary
C.	Zero
D.	Undefined
Answer» C. Zero

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If \[|z|\,=1,(z\ne -1)\]and \[z=x+iy,\]then \[\left( \frac{z-1}{z+1} \right)\] is [RPET 1997]

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