If \[{{z}_{1}},{{z}_{2}}\in C\], then \[amp\,\left( \frac{{{\text{z}}_{\text{1}}}}{{{{\text{\bar{z}}}}_{\text{2}}}} \right)=\]

\[amp\,\left( \frac{{{z}_{1}}}{{{z}_{2}}} \right)\]

\[amp\,({{z}_{1}}{{\overline{z}}_{2}})\]

\[amp\,({{\overline{z}}_{1}}{{z}_{2}})\]

\[amp\,\left( \frac{{{z}_{2}}}{{{{\bar{z}}}_{1}}} \right)\]

If \[{{z}_{1}},{{z}_{2}}\in C\], then \[amp\,\left( \frac{{{\text{z}}_

1.	If \[{{z}_{1}},{{z}_{2}}\in C\], then \[amp\,\left( \frac{{{\text{z}}_{\text{1}}}}{{{{\text{\bar{z}}}}_{\text{2}}}} \right)=\]
A.	\[amp\,({{z}_{1}}{{\overline{z}}_{2}})\]
B.	\[amp\,({{\overline{z}}_{1}}{{z}_{2}})\]
C.	\[amp\,\left( \frac{{{z}_{2}}}{{{{\bar{z}}}_{1}}} \right)\]
D.	\[amp\,\left( \frac{{{z}_{1}}}{{{z}_{2}}} \right)\]
Answer» D. \[amp\,\left( \frac{{{z}_{1}}}{{{z}_{2}}} \right)\]

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If \[{{z}_{1}},{{z}_{2}}\in C\], then \[amp\,\left( \frac{{{\text{z}}_{\text{1}}}}{{{{\text{\bar{z}}}}_{\text{2}}}} \right)=\]

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