If \[{{z}_{1}}\text{ and }{{z}_{2}}\] be complex numbers such that \[{{z}_{1}}\ne {{z}_{2}}\] and \[|{{z}_{1}}|\,=\,|{{z}_{2}}|\]. If \[{{z}_{1}}\] has positive real part and \[{{z}_{2}}\] has negative imaginary part, then \[\frac{({{z}_{1}}+{{z}_{2}})}{({{z}_{1}}-{{z}_{2}})}\]may be [IIT 1986]

If \[{{z}_{1}}\text{ and }{{z}_{2}}\] be complex numbers such that \[{

1.	If \[{{z}_{1}}\text{ and }{{z}_{2}}\] be complex numbers such that \[{{z}_{1}}\ne {{z}_{2}}\] and \[\|{{z}_{1}}\|\,=\,\|{{z}_{2}}\|\]. If \[{{z}_{1}}\] has positive real part and \[{{z}_{2}}\] has negative imaginary part, then \[\frac{({{z}_{1}}+{{z}_{2}})}{({{z}_{1}}-{{z}_{2}})}\]may be [IIT 1986]
A.	Purely imaginary
B.	Real and positive
C.	Real and negative
D.	None of these
Answer» B. Real and positive

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If \[{{z}_{1}}\text{ and }{{z}_{2}}\] be complex numbers such that \[{{z}_{1}}\ne {{z}_{2}}\] and \[|{{z}_{1}}|\,=\,|{{z}_{2}}|\]. If \[{{z}_{1}}\] has positive real part and \[{{z}_{2}}\] has negative imaginary part, then \[\frac{({{z}_{1}}+{{z}_{2}})}{({{z}_{1}}-{{z}_{2}})}\]may be [IIT 1986]

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