If \[y=\frac{1}{1+{{x}^{\beta -\alpha }}+{{x}^{\gamma -\alpha }}}+\frac{1}{1+{{x}^{\alpha -\beta }}+{{x}^{\gamma -\beta }}}+\frac{1}{1+{{x}^{\alpha -\gamma }}+{{x}^{\beta -\gamma }}}\]then \[\frac{dy}{dx}\] is equal to

\[(\alpha +\beta +\gamma ){{x}^{\alpha +\beta +\gamma -1}}\]

If \[y=\frac{1}{1+{{x}^{\beta -\alpha }}+{{x}^{\gamma -\alpha }}}+\fra

1.	If \[y=\frac{1}{1+{{x}^{\beta -\alpha }}+{{x}^{\gamma -\alpha }}}+\frac{1}{1+{{x}^{\alpha -\beta }}+{{x}^{\gamma -\beta }}}+\frac{1}{1+{{x}^{\alpha -\gamma }}+{{x}^{\beta -\gamma }}}\]then \[\frac{dy}{dx}\] is equal to
A.	0
B.	1
C.	\[(\alpha +\beta +\gamma ){{x}^{\alpha +\beta +\gamma -1}}\]
D.	None of these
Answer» B. 1

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If \[y=\frac{1}{1+{{x}^{\beta -\alpha }}+{{x}^{\gamma -\alpha }}}+\frac{1}{1+{{x}^{\alpha -\beta }}+{{x}^{\gamma -\beta }}}+\frac{1}{1+{{x}^{\alpha -\gamma }}+{{x}^{\beta -\gamma }}}\]then \[\frac{dy}{dx}\] is equal to

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