If \[y=y(x)\] and \[\frac{2+\sin x}{1+y}\left( \frac{dy}{dx} \right)=-\cos \,x,y(0)=1,\]then \[y\left( \frac{\pi }{2} \right)\] equals

If \[y=y(x)\] and \[\frac{2+\sin x}{1+y}\left( \frac{dy}{dx} \right)=-

1.	If \[y=y(x)\] and \[\frac{2+\sin x}{1+y}\left( \frac{dy}{dx} \right)=-\cos \,x,y(0)=1,\]then \[y\left( \frac{\pi }{2} \right)\] equals
A.	44256
B.	44257
C.	-0.333333333333333
D.	1
Answer» B. 44257

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If \[y=y(x)\] and \[\frac{2+\sin x}{1+y}\left( \frac{dy}{dx} \right)=-\cos \,x,y(0)=1,\]then \[y\left( \frac{\pi }{2} \right)\] equals

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