If \[{{y}^{x}}+{{x}^{y}}={{a}^{b}}\],then \[\frac{dy}{dx}=\]

1.	If \[{{y}^{x}}+{{x}^{y}}={{a}^{b}}\],then \[\frac{dy}{dx}=\]
A.	\[-\frac{y{{x}^{y-1}}+{{y}^{x}}\log y}{x{{y}^{x-1}}+{{x}^{y}}\log x}\]
B.	\[\frac{y{{x}^{y-1}}+{{y}^{x}}\log y}{x{{y}^{x-1}}+{{x}^{y}}\log x}\]
C.	\[-\frac{y{{x}^{y-1}}+{{y}^{x}}}{x{{y}^{x-1}}+{{x}^{y}}l}\]
D.	\[\frac{y{{x}^{y-1}}+{{y}^{x}}}{x{{y}^{x-1}}+{{x}^{y}}}\]
Answer» B. \[\frac{y{{x}^{y-1}}+{{y}^{x}}\log y}{x{{y}^{x-1}}+{{x}^{y}}\log x}\]

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If \[{{y}^{x}}+{{x}^{y}}={{a}^{b}}\],then \[\frac{dy}{dx}=\]

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