If \[y={{x}^{\sqrt{x}}},\]then \[\frac{dy}{dx}\]=

1.	If \[y={{x}^{\sqrt{x}}},\]then \[\frac{dy}{dx}\]=
A.	\[{{x}^{\sqrt{x}}}\frac{2+\log x}{2\sqrt{x}}\]
B.	\[{{x}^{\sqrt{x}}}\frac{2+\log x}{\sqrt{x}}\]
C.	\[\frac{2+\log x}{2\sqrt{x}}\]
D.	None of these
Answer» B. \[{{x}^{\sqrt{x}}}\frac{2+\log x}{\sqrt{x}}\]

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If \[y={{x}^{\sqrt{x}}},\]then \[\frac{dy}{dx}\]=

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