If \[y={{x}^{\sin x}},\]then \[\frac{dy}{dx}=\] [DSSE 1983, 84]

\[\frac{y[x\cos x.\log x+\cos x]}{x}\]

\[\frac{x\cos x.\log x+\sin x}{x}.{{x}^{\sin x}}\]

If \[y={{x}^{\sin x}},\]then \[\frac{dy}{dx}=\] �

1.	If \[y={{x}^{\sin x}},\]then \[\frac{dy}{dx}=\] [DSSE 1983, 84]
A.	\[\frac{x\cos x.\log x+\sin x}{x}.{{x}^{\sin x}}\]
B.	\[\frac{y[x\cos x.\log x+\cos x]}{x}\]
C.	\[y[x\sin x.\log x+\cos x]\]
D.	None of these
Answer» B. \[\frac{y[x\cos x.\log x+\cos x]}{x}\]

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If \[y={{x}^{\sin x}},\]then \[\frac{dy}{dx}=\] [DSSE 1983, 84]

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