If \[y={{x}^{n}}\log x+x{{(\log x)}^{n}}\], then \[\frac{dy}{dx}=\]

1.	If \[y={{x}^{n}}\log x+x{{(\log x)}^{n}}\], then \[\frac{dy}{dx}=\]
A.	\[{{x}^{n-1}}(1+n\log x)+{{(\log x)}^{n-1}}[n+\log x]\]
B.	\[{{x}^{n-2}}(1+n\log x)+{{(\log x)}^{n-1}}[n+\log x]\]
C.	\[{{x}^{n-1}}(1+n\log x)+{{(\log x)}^{n-1}}[n-\log x]\]
D.	None of these
Answer» B. \[{{x}^{n-2}}(1+n\log x)+{{(\log x)}^{n-1}}[n+\log x]\]

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If \[y={{x}^{n}}\log x+x{{(\log x)}^{n}}\], then \[\frac{dy}{dx}=\]

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