If \[y={{\tan }^{-1}}\sqrt{\frac{1+\cos x}{1-\cos x}}\], then \[\frac{dy}{dx}\] is equal to [Roorkee 1995]

If \[y={{\tan }^{-1}}\sqrt{\frac{1+\cos x}{1-\cos x}}\], then \[\frac{

1.	If \[y={{\tan }^{-1}}\sqrt{\frac{1+\cos x}{1-\cos x}}\], then \[\frac{dy}{dx}\] is equal to [Roorkee 1995]
A.	0
B.	\[-\frac{1}{2}\]
C.	½
D.	1
Answer» C. ½

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If \[y={{\tan }^{-1}}\sqrt{\frac{1+\cos x}{1-\cos x}}\], then \[\frac{dy}{dx}\] is equal to [Roorkee 1995]

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