MCQOPTIONS
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| 1. |
If \[y={{\tan }^{-1}}\left( \frac{x}{\sqrt{1-{{x}^{2}}}} \right)\], then \[\frac{dy}{dx}=\] [MP PET 1999] |
| A. | \[-\frac{1}{\sqrt{1-{{x}^{2}}}}\] |
| B. | \[\frac{x}{\sqrt{1-{{x}^{2}}}}\] |
| C. | \[\frac{1}{\sqrt{1-{{x}^{2}}}}\] |
| D. | \[\frac{\sqrt{1-{{x}^{2}}}}{x}\] |
| Answer» D. \[\frac{\sqrt{1-{{x}^{2}}}}{x}\] | |