If \[y={{\tan }^{-1}}\left( \frac{\sqrt{x}-x}{1+{{x}^{3/2}}} \right),\]then \[y'(1)\] is [AMU 2000]

If \[y={{\tan }^{-1}}\left( \frac{\sqrt{x}-x}{1+{{x}^{3/2}}} \right),\

1.	If \[y={{\tan }^{-1}}\left( \frac{\sqrt{x}-x}{1+{{x}^{3/2}}} \right),\]then \[y'(1)\] is [AMU 2000]
A.	0
B.	\[\frac{1}{2}\]
C.	? 1
D.	\[-\frac{1}{4}\]
Answer» E.

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If \[y={{\tan }^{-1}}\left( \frac{\sqrt{x}-x}{1+{{x}^{3/2}}} \right),\]then \[y'(1)\] is [AMU 2000]

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