If \[y\sqrt{{{x}^{2}}+1}=\log \left\{ \sqrt{{{x}^{2}}+1}-x \right\}\], then\[({{x}^{2}}+1)\frac{dy}{dx}+xy+1=\] [Roorkee 1978; Kurukshetra CEE 1998]

If \[y\sqrt{{{x}^{2}}+1}=\log \left\{ \sqrt{{{x}^{2}}+1}-x \right\}\],

1.	If \[y\sqrt{{{x}^{2}}+1}=\log \left\{ \sqrt{{{x}^{2}}+1}-x \right\}\], then\[({{x}^{2}}+1)\frac{dy}{dx}+xy+1=\] [Roorkee 1978; Kurukshetra CEE 1998]
A.	0
B.	1
C.	2
D.	None of these
Answer» B. 1

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If \[y\sqrt{{{x}^{2}}+1}=\log \left\{ \sqrt{{{x}^{2}}+1}-x \right\}\], then\[({{x}^{2}}+1)\frac{dy}{dx}+xy+1=\] [Roorkee 1978; Kurukshetra CEE 1998]

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