If \[y=\sqrt{\frac{(x-a)(x-b)}{(x-c)(x-d)}}\], then \[\frac{dy}{dx}=\]

1.	If \[y=\sqrt{\frac{(x-a)(x-b)}{(x-c)(x-d)}}\], then \[\frac{dy}{dx}=\]
A.	\[\frac{y}{2}\left[ \frac{1}{x-a}+\frac{1}{x-b}-\frac{1}{x-c}-\frac{1}{x-d} \right]\]
B.	\[y\,\left[ \frac{1}{x-a}+\frac{1}{x-b}-\frac{1}{x-c}-\frac{1}{x-d} \right]\]
C.	\[\frac{1}{2}\left[ \frac{1}{x-a}+\frac{1}{x-b}-\frac{1}{x-c}-\frac{1}{x-d} \right]\]
D.	None of these
Answer» B. \[y\,\left[ \frac{1}{x-a}+\frac{1}{x-b}-\frac{1}{x-c}-\frac{1}{x-d} \right]\]

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If \[y=\sqrt{\frac{(x-a)(x-b)}{(x-c)(x-d)}}\], then \[\frac{dy}{dx}=\]

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