If \[y=\sqrt{\frac{1+x}{1-x}},\]then \[\frac{dy}{dx}=\] [AISSE 1981; RPET 1995]

\[\frac{1}{2{{(1+x)}^{1/2}}{{(1-x)}^{3/2}}}\]

\[\frac{2}{{{(1+x)}^{1/2}}{{(1-x)}^{3/2}}}\]

\[\frac{1}{{{(1+x)}^{1/2}}{{(1-x)}^{3/2}}}\]

\[\frac{1}{{{(1+x)}^{3/2}}{{(1-x)}^{1/2}}}\]

If \[y=\sqrt{\frac{1+x}{1-x}},\]then \[\frac{dy}{dx}=\] [A

1.	If \[y=\sqrt{\frac{1+x}{1-x}},\]then \[\frac{dy}{dx}=\] [AISSE 1981; RPET 1995]
A.	\[\frac{2}{{{(1+x)}^{1/2}}{{(1-x)}^{3/2}}}\]
B.	\[\frac{1}{{{(1+x)}^{1/2}}{{(1-x)}^{3/2}}}\]
C.	\[\frac{1}{2{{(1+x)}^{1/2}}{{(1-x)}^{3/2}}}\]
D.	\[\frac{1}{{{(1+x)}^{3/2}}{{(1-x)}^{1/2}}}\]
Answer» C. \[\frac{1}{2{{(1+x)}^{1/2}}{{(1-x)}^{3/2}}}\]

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If \[y=\sqrt{\frac{1+x}{1-x}},\]then \[\frac{dy}{dx}=\] [AISSE 1981; RPET 1995]

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