If \[y={{\sin }^{2}}\alpha +{{\cos }^{2}}(\alpha +\beta )+2\sin \alpha \sin \beta \cos (\alpha +\beta )\], then \[\frac{{{d}^{3}}y}{d{{\alpha }^{3}}}\] is, (keeping \[\beta \]as constant)

\[\frac{{{\sin }^{3}}(\alpha +\beta )}{\cos \alpha }\]

If \[y={{\sin }^{2}}\alpha +{{\cos }^{2}}(\alpha +\beta )+2\sin \alpha

1.	If \[y={{\sin }^{2}}\alpha +{{\cos }^{2}}(\alpha +\beta )+2\sin \alpha \sin \beta \cos (\alpha +\beta )\], then \[\frac{{{d}^{3}}y}{d{{\alpha }^{3}}}\] is, (keeping \[\beta \]as constant)
A.	\[\frac{{{\sin }^{3}}(\alpha +\beta )}{\cos \alpha }\]
B.	\[\cos (\alpha +3\beta )\]
C.	0
D.	None of these
Answer» D. None of these

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If \[y={{\sin }^{2}}\alpha +{{\cos }^{2}}(\alpha +\beta )+2\sin \alpha \sin \beta \cos (\alpha +\beta )\], then \[\frac{{{d}^{3}}y}{d{{\alpha }^{3}}}\] is, (keeping \[\beta \]as constant)

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