1.

If y = sin-1x, then

A. (1-x2)yn+2 – xyn+1(2n-1) = nyn(2n-1)
B. x2yn+2 – xyn+1(2n-1) = nyn(2n-1)
C. (1-x2)yn+2 – 2nxyn+1 = nyn(2n-1)
D. (1-x2)yn+2 – xyn+1(2n-1) +nyn(2n-1)=0
Answer» B. x2yn+2 – xyn+1(2n-1) = nyn(2n-1)


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