1.

If y = sin-1x, then

A. (1-x<sup>2</sup>)y<sub>n+2</sub> – xy<sub>n+1</sub>(2n-1) = ny<sub>n</sub>(2n-1)
B. x<sup>2</sup>y<sub>n+2</sub> – xy<sub>n+1</sub>(2n-1) = ny<sub>n</sub>(2n-1)
C. (1-x<sup>2</sup>)y<sub>n+2</sub> – 2nxy<sub>n+1</sub> = ny<sub>n</sub>(2n-1)
D. (1-x<sup>2</sup>)y<sub>n+2</sub> – xy<sub>n+1</sub>(2n-1) +ny<sub>n</sub>(2n-1)=0
Answer» B. x<sup>2</sup>y<sub>n+2</sub> ‚Äö√Ñ√∂‚àö√ë‚àö¬® xy<sub>n+1</sub>(2n-1) = ny<sub>n</sub>(2n-1)


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