If \[y={{\sin }^{-1}}\sqrt{1-{{x}^{2}}}\], then \[dy/dx=\] [AISSE 1987]

\[-\frac{1}{\sqrt{{{x}^{2}}-1}}\]

\[\frac{1}{\sqrt{1-{{x}^{2}}}}\]

\[\frac{1}{\sqrt{1+{{x}^{2}}}}\]

\[-\frac{1}{\sqrt{1-{{x}^{2}}}}\]

If \[y={{\sin }^{-1}}\sqrt{1-{{x}^{2}}}\], then \[dy/dx=\]

1.	If \[y={{\sin }^{-1}}\sqrt{1-{{x}^{2}}}\], then \[dy/dx=\] [AISSE 1987]
A.	\[\frac{1}{\sqrt{1-{{x}^{2}}}}\]
B.	\[\frac{1}{\sqrt{1+{{x}^{2}}}}\]
C.	\[-\frac{1}{\sqrt{1-{{x}^{2}}}}\]
D.	\[-\frac{1}{\sqrt{{{x}^{2}}-1}}\]
Answer» D. \[-\frac{1}{\sqrt{{{x}^{2}}-1}}\]

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If \[y={{\sin }^{-1}}\sqrt{1-{{x}^{2}}}\], then \[dy/dx=\] [AISSE 1987]

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