MCQOPTIONS
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| 1. |
If \[y={{\sin }^{-1}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right)\], then \[\frac{dy}{dx}\] equals [EAMCET 1991; RPET 1996] |
| A. | \[\frac{2}{1-{{x}^{2}}}\] |
| B. | \[\frac{1}{1+{{x}^{2}}}\] |
| C. | \[\pm \frac{2}{1+{{x}^{2}}}\] |
| D. | \[-\frac{2}{1+{{x}^{2}}}\] |
| Answer» D. \[-\frac{2}{1+{{x}^{2}}}\] | |