If \[y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}},\]where \[0

1.	If \[y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}},\]where \[0
A.	\[\frac{2}{1+{{x}^{2}}}\]
B.	\[\frac{2x}{1+{{x}^{2}}}\]
C.	\[\frac{-2}{1+{{x}^{2}}}\]
D.	\[\frac{-x}{1+{{x}^{2}}}\]
Answer» B. \[\frac{2x}{1+{{x}^{2}}}\]

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If \[y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}},\]where \[0

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