1.

If \[y=\sec {{x}^{0}}\], then \[\frac{dy}{dx}=\]                                                             [MP PET 1997]

A.            \[\sec x\tan x\]
B.            \[\sec {{x}^{o}}\tan {{x}^{o}}\]
C.  \[\frac{\pi }{180}\sec {{x}^{o}}\tan {{x}^{o}}\]
D.   \[\frac{180}{\pi }\sec {{x}^{o}}\tan {{x}^{o}}\]
Answer» D.   \[\frac{180}{\pi }\sec {{x}^{o}}\tan {{x}^{o}}\]


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