If \[y={{\sec }^{-1}}\left( \frac{\sqrt{x}+1}{\sqrt{x}-1} \right)+{{\sin }^{-1}}\left( \frac{\sqrt{x}-1}{\sqrt{x}+1} \right)\], then \[\frac{dy}{dx}=\] [UPSEAT 1999; AMU 2002; Kerala (Engg.) 2005]

If \[y={{\sec }^{-1}}\left( \frac{\sqrt{x}+1}{\sqrt{x}-1} \right)+{{\s

1.	If \[y={{\sec }^{-1}}\left( \frac{\sqrt{x}+1}{\sqrt{x}-1} \right)+{{\sin }^{-1}}\left( \frac{\sqrt{x}-1}{\sqrt{x}+1} \right)\], then \[\frac{dy}{dx}=\] [UPSEAT 1999; AMU 2002; Kerala (Engg.) 2005]
A.	0
B.	\[\frac{1}{\sqrt{x}+1}\]
C.	1
D.	None of these
Answer» B. \[\frac{1}{\sqrt{x}+1}\]

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If \[y={{\sec }^{-1}}\left( \frac{\sqrt{x}+1}{\sqrt{x}-1} \right)+{{\sin }^{-1}}\left( \frac{\sqrt{x}-1}{\sqrt{x}+1} \right)\], then \[\frac{dy}{dx}=\] [UPSEAT 1999; AMU 2002; Kerala (Engg.) 2005]

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