If \[y=\log \frac{1+\sqrt{x}}{1-\sqrt{x}},\]then \[\frac{dy}{dx}=\]

1.	If \[y=\log \frac{1+\sqrt{x}}{1-\sqrt{x}},\]then \[\frac{dy}{dx}=\]
A.	\[\frac{\sqrt{x}}{1-x}\]
B.	\[\frac{1}{\sqrt{x}(1-x)}\]
C.	\[\frac{\sqrt{x}}{1+x}\]
D.	\[\frac{1}{\sqrt{x}(1+x)}\]
Answer» C. \[\frac{\sqrt{x}}{1+x}\]

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If \[y=\log \frac{1+\sqrt{x}}{1-\sqrt{x}},\]then \[\frac{dy}{dx}=\]

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