If \[y={{\log }_{\cos x}}\sin x\], then \[\frac{dy}{dx}\]is equal to

1.	If \[y={{\log }_{\cos x}}\sin x\], then \[\frac{dy}{dx}\]is equal to
A.	\[\frac{\cot x\log \cos x+\tan x\log \sin x}{{{(\log \cos x)}^{2}}}\]
B.	\[\frac{\tan x\log \cos x+\cot x\log \sin x}{{{(\log \cos x)}^{2}}}\]
C.	\[\frac{\cot x\log \cos x+\tan x\log \sin x}{{{(\log \sin x)}^{2}}}\]
D.	None of these
Answer» B. \[\frac{\tan x\log \cos x+\cot x\log \sin x}{{{(\log \cos x)}^{2}}}\]

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If \[y={{\log }_{\cos x}}\sin x\], then \[\frac{dy}{dx}\]is equal to

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