If \[y={{\left( x+\sqrt{{{x}^{2}}+{{a}^{2}}} \right)}^{n}}\], then \[\frac{dy}{dx}\]is

\[-\frac{ny}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]

\[\frac{ny}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]

\[\frac{nx}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]

\[-\frac{nx}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]

If \[y={{\left( x+\sqrt{{{x}^{2}}+{{a}^{2}}} \right)}^{n}}\], then \[\

1.	If \[y={{\left( x+\sqrt{{{x}^{2}}+{{a}^{2}}} \right)}^{n}}\], then \[\frac{dy}{dx}\]is
A.	\[\frac{ny}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]
B.	\[-\frac{ny}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]
C.	\[\frac{nx}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]
D.	\[-\frac{nx}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]
Answer» B. \[-\frac{ny}{\sqrt{{{x}^{2}}+{{a}^{2}}}}\]

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If \[y={{\left( x+\sqrt{{{x}^{2}}+{{a}^{2}}} \right)}^{n}}\], then \[\frac{dy}{dx}\]is

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